Free rounds in 4-player perekidnoi tournaments
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Hi, I've recently started playing these tournaments and it's not a great tournament if there are 7 participants - you get a free round after one round. So here's a suggestion: 1) If one person gets a free round, there's nothing you can do - you get 2 points for the free round 2) If the free round should be given to 2 people, then let them play the game together at the table (maybe with a 36-card deck?) - we'll give the winner 3 points, the loser 1 point 3) If the free round should be given to 3 people, let them play together at the table - we'll give 3, 1 and 0 points respectively. How does the idea sound?
I didn't really understand what game you were talking about. Could someone tell me what game you were talking about?
It seems like a poor win, because in chess around the world, 2 points are awarded for a free round (just like a win)
[i]posted 1341[/i] I didn't really get what game you're talking about. Can someone tell me what game you're talking about?
It's about a family of 4.
It's better if a computer comes to the rescue.
It's even worse when there are 4 tables playing, if there are 7 players then only four play... if there are 9 players then only 8 players play and the one with the weakest raid is out of the game.
The computer still doesn't work, it runs so fast that others have no hope.
The points could be divided 4/2/0. A win is a win and it is no easier to win at table three than at table four. If 1 hand leaves the table four right at the beginning, the winner still gets 4 points...... so why not divide the points 3/1/0???
In any case, the option where you get 3/1/0 points at the 3rd table is not suitable, because the scoring system is still structured in such a way that there are 2 points per/face in the game. There are 8 points available at the 4th table and in the free round everyone gets 2, so there should be 6 points left at the 3rd table. That would be fair.
Would the three weakest players in the tournament table be in the three-table, or would the three-table be determined based on the same system as the free rounds? I would suggest that for 6, 9 players, all tables could be 3-tables. PS! For 7 participants, two tables of 3 could also be used. Each player would only have 1 free round instead of 3-4. In these variants, no one would have an advantage. Just luck of the game is needed.