), so maybe a pro can help? I'll add a picture of this sudoku here, I copied it onto another piece of paper, so it's not in print, but you should still understand. Help with solving Estonian sudoku
Read by 28 users
Although I solved most of the sudokus in Estonian, some (9/29) remained unsolved/incomplete/wrong. I have solved 8 of them beautifully later, but 1 is one that I have not found a solution to. I even used notes and tried different methods, including combinations, but still could not find a solution. I assume that this is not the kind of sudoku that requires a 50-50 decision (these are not real sudokus). ), so maybe a pro can help? I'll add a picture of this sudoku here, I copied it onto another piece of paper, so it's not in print, but you should still understand.
), so maybe a pro can help? I'll add a picture of this sudoku here, I copied it onto another piece of paper, so it's not in print, but you should still understand. 
I'm not a pro, but I can give you one way to solve this sudoku. I mark the squares starting from the top left corner, for example, the 6 in the top row is in square R1C2.
1. If R6C5 were 3 then R7C4, R9C1 and R5C3 would also be 3, but in this case both R4C5 and R4C3 should be 1, so the 3 is instead in the squares R6C4, R9C5, R7C3 and R5C1.
2. Since the square R7C4 is either 5 or 7, then R4C4 and R7C2 must be the same and the same number must also be in the square R5C3. R5C3 cannot be 5, which implies that R4C4, R7C2, and R5C3 are 7.
From there it should be pretty easy.
1. If R6C5 were 3 then R7C4, R9C1 and R5C3 would also be 3, but in this case both R4C5 and R4C3 should be 1, so the 3 is instead in the squares R6C4, R9C5, R7C3 and R5C1.
2. Since the square R7C4 is either 5 or 7, then R4C4 and R7C2 must be the same and the same number must also be in the square R5C3. R5C3 cannot be 5, which implies that R4C4, R7C2, and R5C3 are 7.
From there it should be pretty easy.
Okay, thanks, I got it resolved.
Regarding point 1, I understand, although I can't see why it would be necessary to start experimenting with 3 in R6C5, i.e. I wouldn't think of it. In that situation, is there just a random square chosen to experiment with?
Regarding point 2, I don't understand why square R5C3 has to have the same number as squares R4C4 and R7C2, but I can work it out in a similar way: if R7C4 is 7, then R7C2 and R4C4 must be 5, but in this case in the 3x3 box 2.1 (if you mark the top boxes from the left as 1.1, 1.2, 1.3 and the middle ones as 2.1, 2.2, 2.3) the 5 can't go anywhere, so R7C4 can't be 7, so it has to be 5. But again, this is a situation where you have to experiment, so I wouldn't normally come up with it myself. I'm used to the fact that it can be solved without such experimentation and thinking ahead.
After that, it will be resolved nicely.
Regarding point 1, I understand, although I can't see why it would be necessary to start experimenting with 3 in R6C5, i.e. I wouldn't think of it. In that situation, is there just a random square chosen to experiment with?
Regarding point 2, I don't understand why square R5C3 has to have the same number as squares R4C4 and R7C2, but I can work it out in a similar way: if R7C4 is 7, then R7C2 and R4C4 must be 5, but in this case in the 3x3 box 2.1 (if you mark the top boxes from the left as 1.1, 1.2, 1.3 and the middle ones as 2.1, 2.2, 2.3) the 5 can't go anywhere, so R7C4 can't be 7, so it has to be 5. But again, this is a situation where you have to experiment, so I wouldn't normally come up with it myself. I'm used to the fact that it can be solved without such experimentation and thinking ahead.
After that, it will be resolved nicely.